At ACME College students concentrate in one of three areas: pre-med, pre-law, or theater-arts. Only 15% of the students are theater-arts majors, with the remaining population divided equally among pre-med and pre-law.

At ACME College students concentrate in one of three areas: pre-med,

pre-law, or theater-arts. Only 15% of the students are theater-arts majors, with the remaining population divided equally among pre-med and pre-law. The most popular intramural sport at this college is ultimate frisbee, but participation differs between concentrations. Only 10% of pre-med students play on a frisbee squad, while 20% of pre-law students do, and 80% of theater-arts students do.
Suppose someone in your study group shows up wearing an ultimate frisbee t- shirt with ACME’s logo on it (which you take as certain evidence that she played ultimate frisbee while at ACME). What is the probability that this student was a theater-arts major?
Group of answer choices

0.8

0.15

0.34

0.12

0.48

 
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Eeight O-rings were produced and subjected to a nitric acid bath, following which the tensile strength of each O-ring was determined. What type of poulation is this considered to be? A study or an experiment where the conclusions are to be drawn relative to a future population is called:

Eeight O-rings were produced and subjected to a nitric acid bath,

following which the tensile strength of each O-ring was determined. What type of poulation is this considered to be?

A study or an experiment where the conclusions are to be drawn relative to a future population is called:

 
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Answer T (true) or F (false ). 1. For a normally distributed population of heights of 10,000 women, m = 63 inches and s = 5 inches. The number of heights in the population that fall between 66 and 68 inches is 1156. 2. In a normal distribution, approximately 91.31% of the area under the curve is found to the right of a point -1.36 standard deviations from the mean. 3. Approximately 92.5% of the area under the normal curve is located between the mean and +/- 1.78 standard deviations from the mean.

Answer T (true) or F (false

).

1.     For a normally distributed population of heights of 10,000 women, m = 63 inches and s = 5 inches.

The number of heights in the population that fall between 66 and 68 inches is 1156.

2. In a normal distribution, approximately 91.31% of the area under the curve is found to the right of a

point -1.36 standard deviations from the mean.

3. Approximately 92.5% of the area under the normal curve is located between the mean and

+/- 1.78 standard deviations from the mean.

 
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Hi! I’m currently taking a stats class, and I am struggling…I have a TI-30XS calculator and am wondering if anyone can teach me how to plug in the numbers correctly to have it give me the binomial distribution sum? Or help me work out the question long hand? I am not wanting to use your work, simply better understand how to figure binomial distribution.

Hi! I’m currently taking a stats class, and I am struggling…I have

a TI-30XS calculator and am wondering if anyone can teach me how to plug in the numbers correctly to have it give me the binomial distribution sum? Or help me work out the question long hand? I am not wanting to use your work, simply better understand how to figure binomial distribution.

 
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Suppose that, on average, in a Whole Foods Market in Dallas, 3.4 customers want to check out every minute. Based on this figure, store management wants to staff checkout lines such that less than 1% of the time demand for checkout cannot be met. In this case, store management would have to staff for what number of customers? Based on the 3.4 customer average per minute, what percentage of the time would the store have 12 or more customers who want to check out in any two-minute period?

Suppose that, on average, in a Whole Foods Market in Dallas, 3.4 customers

want to check out every minute. Based on this figure, store management wants to staff checkout lines such that less than 1% of the time demand for checkout cannot be met. In this case, store management would have to staff for what number of customers? Based on the 3.4 customer average per minute, what percentage of the time would the store have 12 or more customers who want to check out in any two-minute period?

 
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a simple linear regression model, if the plots on a scatter diagram lie on a straight line, what is the standard error of the

a simple linear regression model, if the plots on a scatter diagram

lie on a straight line, what is the standard error of the

 
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A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results: Social Activity Education Above Average Average Below Average College 30 20 10 High School 20 40 90 Grade School 10 50 130 What is the value of the chi-square test statistic? A) 100 B) 83.67 C) 50 D) 4.94 please explain how you find the answer

A recent study of the relationship between social activity and education for a sample of corporate executives showed the following results:

Social Activity

Education Above Average Average Below Average
College 30 20 10
High School 20 40 90
Grade School 10 50 130

 

What is the value of the chi-square test statistic?

A) 100

B) 83.67

C) 50

D) 4.94

please explain how you find the answer

 
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Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A sample of 100 steady smokers revealed that the sample mean is $20. And we know the population standard deviation is $5. What is the probability that a sample of 100 steady smokers spend between $19 and $21? A) 0.0091 B) 0.9818 C) 0.4909 D) 0.9544 Can you please show work we can use a Z-score table sheet

Suppose a research firm conducted a survey to determine the mean

amount steady smokers spend on cigarettes during a week. A sample of 100 steady smokers revealed that the sample mean is $20. And we know the population standard deviation is $5. What is the probability that a sample of 100 steady smokers spend between $19 and $21?
A) 0.0091
B) 0.9818
C) 0.4909
D) 0.9544
Can you please show work
we can use a Z-score table sheet

 
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The Intelligence Quotient (IQ) test scores for adults are normally distributed with a mean of 100 and a standard deviation of 15. What is the probability we could select a sample of 50 adults and find the mean of this sample is less than 95? We can use a Z-score sheet/table The answer is 0.0091 where the Z-score =2.36 Not sure how this was done

The Intelligence Quotient (IQ) test scores for adults are normally

  1. distributed with a mean of 100 and a standard deviation of 15.  What is the probability we could select a sample of 50 adults and find the mean of this sample is less than 95?

    We can use a Z-score sheet/table
    The answer is 0.0091 where the Z-score =2.36 Not sure how this was done

 
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A sample of n = 100 scores is selected from a population with μ= 80 with σ= 20. On average, how much error is expected between the sample mean and the population mean? A) 0.2 points B) 0.8 points C) 2 points D) 4 points

A sample of n = 100 scores is selected from a population with μ= 80

with σ= 20.  On average, how much error is expected between the sample mean and the population mean?

A) 0.2 points
B) 0.8 points
C) 2 points
D) 4 points

 
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